{an}满足a1=2,an+1=3an+3^(n+1)-2^n（n∈正整数）,设bn=(an-2^n)/3^n,证明bn为等差数列,并求an的通项公式

数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知{an}满足a1=1.an=3*n+2An-1,求an 已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列 已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an 数列{an}满足a1=a,an+1=1+1/an.若3/2 数列an满足a1=1/3,Sn=n(2n-1)an,求an 数列[An]满足a1=2,a（n+1）=3an-2 求an 数列{an}满足a1=1 an+1=2n+1an/an+2n 数列an满足a1=2,an+1=4an+9,则an=? 数列[An]满足An+1-An+3=0,且A1=-5.求An. 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 数列an满足a1=2,an+1=an²求an 数列an满足a1=2,an+1=an²求an 已知数列an满足a1=1,a(n+1)=an/(3an+2),则an=? 数列an满足a1=1/2 an+1=an/(2an+3) 猜想数列通项公式 数列{an}满足a1=1,an=3n+2an-1(n≥2)求an