(1) y-(y-1)/2=2-(y+2)/5 (2) (2x-1)/3-(10x+1)/12=(2x+1)/4-1y-(y-1)/2=2-(y+2)/5(2x-1)/3-(10x+1)/12=(2x+1)/4-1

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/08 02:35:10
(1) y-(y-1)/2=2-(y+2)/5 (2) (2x-1)/3-(10x+1)/12=(2x+1)/4-1y-(y-1)/2=2-(y+2)/5(2x-1)/3-(10x+1)/12=(2x+1)/4-1

(1) y-(y-1)/2=2-(y+2)/5 (2) (2x-1)/3-(10x+1)/12=(2x+1)/4-1y-(y-1)/2=2-(y+2)/5(2x-1)/3-(10x+1)/12=(2x+1)/4-1
(1) y-(y-1)/2=2-(y+2)/5 (2) (2x-1)/3-(10x+1)/12=(2x+1)/4-1
y-(y-1)/2=2-(y+2)/5
(2x-1)/3-(10x+1)/12=(2x+1)/4-1

(1) y-(y-1)/2=2-(y+2)/5 (2) (2x-1)/3-(10x+1)/12=(2x+1)/4-1y-(y-1)/2=2-(y+2)/5(2x-1)/3-(10x+1)/12=(2x+1)/4-1
(1) 10y-5(y-1)=20-2(y+2)
10y-5y+5=20-2y-4
10y-5y+2y=20-4-5
7y=11
y=11/7
(2) 4(2x-1)-(10x+1)=3(2x+1)-12
8x-4-10x-1=6x+3-12
8x-10x-6x=3-12+4+1
-8x=-4
x=1/2