解方程1/2{1/3[1/4(1/5x+5)-4]+3}=1① 1/2{1/3[1/4(1/5x+5)-4]+3}=1②2[1-1/3( x- x+1/3 )]=3[x/6-1/2(2x - 10-7x/3)]

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解方程1/2{1/3[1/4(1/5x+5)-4]+3}=1① 1/2{1/3[1/4(1/5x+5)-4]+3}=1②2[1-1/3( x- x+1/3 )]=3[x/6-1/2(2x - 10-7x/3)]

解方程1/2{1/3[1/4(1/5x+5)-4]+3}=1① 1/2{1/3[1/4(1/5x+5)-4]+3}=1②2[1-1/3( x- x+1/3 )]=3[x/6-1/2(2x - 10-7x/3)]
解方程1/2{1/3[1/4(1/5x+5)-4]+3}=1
① 1/2{1/3[1/4(1/5x+5)-4]+3}=1
②2[1-1/3( x- x+1/3 )]=3[x/6-1/2(2x - 10-7x/3)]

解方程1/2{1/3[1/4(1/5x+5)-4]+3}=1① 1/2{1/3[1/4(1/5x+5)-4]+3}=1②2[1-1/3( x- x+1/3 )]=3[x/6-1/2(2x - 10-7x/3)]
① 1/2{1/3[1/4(1/5x+5)-4]+3}=1
两边乘以2得
1/3[1/4(1/5x+5)-4]+3=2
1/3[1/4(1/5x+5)-4]=-1
两边乘以3得
1/4(1/5x+5)-4=-3
1/4(1/5x+5)=1
两边乘以4得
1/5x+5=4
1/5x=-1
x=-5



②2[1-1/3( x- x+1/3 )]=3[x/6-1/2(2x - 10-7x/3)]
2-2/3[x-(x+1)/3]=x/2-3/2[2x-(10-7x)/3]
2-2x/3+2(x+1)/9=x/2-3x+(10-7x)/2
两边乘以18得
36-12x+4(x+1)=9x-54x+9(10-7x)
36-12x+4x+4=-45x+90-63x
101x=50
x=50/101