(1)x^2+x-5=0 (2)x^2-(3/2)x+3=0

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(1)x^2+x-5=0 (2)x^2-(3/2)x+3=0

(1)x^2+x-5=0 (2)x^2-(3/2)x+3=0
(1)x^2+x-5=0 (2)x^2-(3/2)x+3=0

(1)x^2+x-5=0 (2)x^2-(3/2)x+3=0
嬲,这么容易(1)公式法a=1 b=1 c=-5 b^2-4ac=21 所以x1 x2 =2a/-b+根号下面b^2-4ac=1+-根号21 (2)这题也用公式法,好解