已知 3sin(π+α)+cos(-α)/4sin(-α)-cos(9π+α)=2,则tan α=2- tan α=α,则sin(-5π-α)cos(3π+α)=

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已知 3sin(π+α)+cos(-α)/4sin(-α)-cos(9π+α)=2,则tan α=2- tan α=α,则sin(-5π-α)cos(3π+α)=

已知 3sin(π+α)+cos(-α)/4sin(-α)-cos(9π+α)=2,则tan α=2- tan α=α,则sin(-5π-α)cos(3π+α)=
已知 3sin(π+α)+cos(-α)/4sin(-α)-cos(9π+α)=2,则tan α=
2- tan α=α,则sin(-5π-α)cos(3π+α)=

已知 3sin(π+α)+cos(-α)/4sin(-α)-cos(9π+α)=2,则tan α=2- tan α=α,则sin(-5π-α)cos(3π+α)=
1,
3sin(π+α)+cos(-α)/4sin(-α)-cos(9π+α)=2,
【-3sinα+cosα】/【-4sinα+cosα】=2,
-3sinα+cosα=-8sinα+2cosα
5sinα=cosα
tan α=sinα/cosα=1/5
2,
tan α=α
sin(-5π-α)cos(3π+α)=sin(π-α)cos(π+α)= -sinαcosα=-sinαcosα/(sin²α+cos²α)=-tanα/(tan²α+1)=-α/(α²+1)