作业帮确定函数f(x)=log1/2[根号2*sin(x-pai/4)]的单调区间
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/14 13:05:55
![确定函数f(x)=log1/2[根号2*sin(x-pai/4)]的单调区间](/uploads/image/z/5264822-38-2.jpg?t=%E7%A1%AE%E5%AE%9A%E5%87%BD%E6%95%B0f%28x%29%3Dlog1%2F2%5B%E6%A0%B9%E5%8F%B72%2Asin%28x-pai%2F4%29%5D%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4)
确定函数f(x)=log1/2[根号2*sin(x-pai/4)]的单调区间
确定函数f(x)=log1/2[根号2*sin(x-pai/4)]的单调区间
确定函数f(x)=log1/2[根号2*sin(x-pai/4)]的单调区间
由题意知sin(x-π/4)>0
则x-π/4∈(2kπ,π+2kπ),k∈Z
因为底数1/2
f(x)=log1/2[根号2*sin(x-pai/4)]
=-1/2-log2 sin(x-pai/4)
0
此时3π/4<=x<5π/4