x2+y2+2xy-2x-2y+1=0分解因式

已知x2+4y2+x2y2+1=6xy,则(x4-y4)/(2x2+xy-y2)*(2x-y)/(xy-y2)/(x2+y2/y)2= 解方程组 ｛3x2-y2=8 {4x2+12xy+9y2=1 {x2+2xy+y2-4=0 x2+xy+y2=4 4x2-9y2=0 x2-2xy+y2-1=0还有{x2+y2=4xy-y2+4=0x2-----x的平方 y2------y的平方 还有{2x-3y=12x2-3xy+y2-4x+3y-3=0 已知x2+y2+4x-2y+5=0,求x2+2xy+y2值 若X2+Y2-2X-6Y+10=0 ,求（x2-y2)/xy的值 已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以（x2+y2/xy）2乘1/x+y的值 若2x+y=0则(x2+xy+y2)/(2xy-x2)的值 已知x2+2xy-2x+y2-2y+1=0,则x+y等于 若x2-2xy-y2-x+Y-1=0 求x-y的值 若x2-2xy-y2-x+Y-1=0 求x-y的值 (x+y)(x+y+1)=0 求x2+y2+2xy的值 思考题：先化简,再求值：(xy-y2)÷x2-2xy+y2/y×x2-y2/y2,其中x=1/2,y=-1 x2-2xy-3y2=0,其中x,y均不为零,求（y-x）/x2-xy/2x-y-y2/xy-x x2-2xy+y2=4 x2+y2-x-y=6 解不等式x2-2xy+y2=4 x2+y2-x-y=6 解不等式 已知X2-2x+y2+6y+10=0,求（x2-2xy）/(xy+y2)的值 已知y/x=1/2,求(x2+2xy+y2)/﹙x2-xy-2y2)的值. x2+2y2-2xy-2y+1=0求：x+2y的值 已知x-y+1,X2+Y2=25 求（x+y）2和x2-xy+y2的值 已知X2+Y2+8X+6Y+25=0 求代数式X2++XY+4Y2分之X2-4Y2 减X+2Y分之X的值