(3X+2)^2-4X^2=05(2X-1)=(1-2X)(X+3)

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(3X+2)^2-4X^2=05(2X-1)=(1-2X)(X+3)

(3X+2)^2-4X^2=05(2X-1)=(1-2X)(X+3)
(3X+2)^2-4X^2=0
5(2X-1)=(1-2X)(X+3)

(3X+2)^2-4X^2=05(2X-1)=(1-2X)(X+3)
1、可分解成（3x+2+2x)(3x+2-2x)=0根据平方差公式,解得x1=-2,x2=-2/5
2、5（2x-1)+(2x-1)(x-3)=0
(2x+1）（5+x-3)=0解得x1=0.5,x2=-2

1.(x+2)(5x+2)=0
因此x=-2或-2/5
2.(2x-1)(2-x)=0
因此x=1/2或2

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