作业帮在△ABC中,角ACB=90°,AC=BC,AE是BC边上的中线,过C作CF⊥AE与F,过B作BD⊥BC交CF的延长线于D,说明：AE=C提示：因为角ACF与角DCB互余 角DCB与角BDC互余 所以角ACF等于角BDC 且角DBC等于角ACE等于90度 且 边BC
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/11 22:31:01
在△ABC中,角ACB=90°,AC=BC,AE是BC边上的中线,过C作CF⊥AE与F,过B作BD⊥BC交CF的延长线于D,说明：AE=C提示：因为角ACF与角DCB互余 角DCB与角BDC互余 所以角ACF等于角BDC 且角DBC等于角ACE等于90度 且 边BC
在△ABC中,角ACB=90°,AC=BC,AE是BC边上的中线,过C作CF⊥AE与F,过B作BD⊥BC交CF的延长线于D,说明：AE=C
提示：因为角ACF与角DCB互余 角DCB与角BDC互余 所以角ACF等于角BDC 且角DBC等于角ACE等于90度 且 边BC等于AC 所以可证明三角形BCD全等与三角形AEC 所以得出AE等于CD
⊙﹏⊙b 汗为什么都没人回答？、
"谈笑人间散"，
在△ABC中,角ACB=90°,AC=BC,AE是BC边上的中线,过C作CF⊥AE与F,过B作BD⊥BC交CF的延长线于D,说明：AE=C提示：因为角ACF与角DCB互余 角DCB与角BDC互余 所以角ACF等于角BDC 且角DBC等于角ACE等于90度 且 边BC
AC=BC,AE是BC中线,CE/AC=1/2,CD垂直AE于F点,∠AEC=∠FEC,所以三角形ACE相似于三角形CFE,CE/CF=AE/AC;
同理因为∠BCD=∠FCE且BD垂直于BC,所以有三角形BDC相似于三角形FEC,CD/BC=CE/CF;
综上,CD/BC=AE/AC,且有BC=AC;所以CD=AE
相关的主题文章：
As you know,Designer Purses, Classic UGG fashion boots will let you to be more warm
during the winter.And with the good Australia wool good material.This
clas...
全部展开
相关的主题文章：
As you know,Designer Purses, Classic UGG fashion boots will let you to be more warm
during the winter.And with the good Australia wool good material.This
classic style discount UGG Boots, joy and generous overall design, light
and color and fall is in line with the atmosphere, combined with the
comfort of a casual denim shorts with an alternative style of cheap
UGG boots. Stitching design snow boots,UGG Baby Boots, super soft plush comfort and
fashion to the natural grace and elegance can easily give you a burst
single step,PUMA Ferrari Shoes, the hair bulb is designed to give you the feeling of a dream
princess, wearing the more appropriate for fall. Even white on sale
UGG boots with a white shirt.You can worn it,The feeling is very good!
收起
你的问题是要求证AE=C? 确定？
#24,这个 你去找老师问吧，就说给他20悬赏分 也许他会很高兴的#24，