y=log2(3-2x-x^2)单调递减区间1,求y=log2(3-2x-x^2)的单调递减区间2,-9,a1,a2,-1是等差数列,-9,b1,b2,b3,-1是等比数列,求b2(a2-a1)的值

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y=log2(3-2x-x^2)单调递减区间1,求y=log2(3-2x-x^2)的单调递减区间2,-9,a1,a2,-1是等差数列,-9,b1,b2,b3,-1是等比数列,求b2(a2-a1)的值

y=log2(3-2x-x^2)单调递减区间1,求y=log2(3-2x-x^2)的单调递减区间2,-9,a1,a2,-1是等差数列,-9,b1,b2,b3,-1是等比数列,求b2(a2-a1)的值
y=log2(3-2x-x^2)单调递减区间
1,求y=log2(3-2x-x^2)的单调递减区间
2,-9,a1,a2,-1是等差数列,-9,b1,b2,b3,-1是等比数列,求b2(a2-a1)的值

y=log2(3-2x-x^2)单调递减区间1,求y=log2(3-2x-x^2)的单调递减区间2,-9,a1,a2,-1是等差数列,-9,b1,b2,b3,-1是等比数列,求b2(a2-a1)的值
1.满足3-2x-x^2>0且f=3-2x-x^2为单调减区间
求得为[-1,1]
2.公差d=(-1+9)/3=8/3
故a2-a1=d=8/3
由b2*b2=9得b2=3或-3
由b2=-9q^2得b2

单调递减区间应该是-1使3-2x-x^2>0 解得-3又因为对数函数的底数为2,因此它是增函数,想求减区间,就应该求3-2x-x^2的减区间,画抛物线,对称轴为X=-1,所以单调递减区间应该是-1

单调递减区间 -1