关于1880年恩格尔曼实验证明光合作用的疑问.实验说,把水绵放在无空气黑暗环境中.= = 光合作用是需要水和二氧化碳做原料的不是么?= = 如果放在无空气环境中,就算水可以来自水绵本身自己

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关于1880年恩格尔曼实验证明光合作用的疑问.实验说,把水绵放在无空气黑暗环境中.= = 光合作用是需要水和二氧化碳做原料的不是么?= = 如果放在无空气环境中,就算水可以来自水绵本身自己

关于1880年恩格尔曼实验证明光合作用的疑问.实验说,把水绵放在无空气黑暗环境中.= = 光合作用是需要水和二氧化碳做原料的不是么?= = 如果放在无空气环境中,就算水可以来自水绵本身自己
关于1880年恩格尔曼实验证明光合作用的疑问.
实验说,把水绵放在无空气黑暗环境中.= = 光合作用是需要水和二氧化碳做原料的不是么?= = 如果放在无空气环境中,就算水可以来自水绵本身自己储存的,可是去哪里找二氧化碳啊?= 没有二氧化碳怎么进行光合作用啊?
应该不是线粒体用氧呼吸产生的二氧化碳,因为用氧呼吸需要氧气,如果没有空气,那么有氧呼吸也是无法进行的.=

关于1880年恩格尔曼实验证明光合作用的疑问.实验说,把水绵放在无空气黑暗环境中.= = 光合作用是需要水和二氧化碳做原料的不是么?= = 如果放在无空气环境中,就算水可以来自水绵本身自己
这个只要对光合作用熟悉一点就知道了,光合作用放出氧气的阶段是在光反应阶段,只需要有水和光能就行,水会光解变成氧气溢出和还原H,至于二氧化碳是在光合作用的暗反应,没有二氧化碳是无法产生有机物的,因此这个光合作用进行的不完全,但仍可产生氧气.

隐之界的答案其实已经说明了,我只是补充一下的。
水绵是水生藻类,生活在水中。恩格尔曼用好氧细菌进行实验,其实所谓的无空气环境是指无氧气的环境就行了。这种实验不可能在真空中进行的。当时的科学条件也不允许。
不过,我们当它是连CO2都没有来看看。
一、光合作用的光反应不需要暗反应支持,光反应在光下把H2O进行光解,就能产生O2。恩格尔曼用一束光线进行实验,为水绵的叶绿体提供了光...

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隐之界的答案其实已经说明了,我只是补充一下的。
水绵是水生藻类,生活在水中。恩格尔曼用好氧细菌进行实验,其实所谓的无空气环境是指无氧气的环境就行了。这种实验不可能在真空中进行的。当时的科学条件也不允许。
不过,我们当它是连CO2都没有来看看。
一、光合作用的光反应不需要暗反应支持,光反应在光下把H2O进行光解,就能产生O2。恩格尔曼用一束光线进行实验,为水绵的叶绿体提供了光。但光反应也受限于叶绿体基质中的NADP+、ADP、Pi等物质的含量,不能持续进行下去。
二、其实水绵无氧状态也能进行无氧呼吸,产生CO2;
而光合作用产生O2,绝对能满足细胞有氧细胞的需要。细胞通过有氧呼吸产生CO2。
产生的CO2能为光合作用提供原料。
三、由于呼吸作用为光合作用提供CO2,所以光合作用的暗反应得以进行。暗反应得以进行后,光反应也能持续进行了。

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Long knee-deep paragraph dust coat is always grace promising, match on black silk plus boots better highlighted perfect legs curve, plus a black bag generous and intellectual. Military green seems win...

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