select *from A where A.a like '%1%'||'%'

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/03 02:02:17
select *from A where A.a like '%1%'||'%'

select *from A where A.a like '%1%'||'%'
select *from A where A.a like '%1%'||'%'

select *from A where A.a like '%1%'||'%'
在什么数据库管理系统?
确定这个可以执行?
在sql server 2005上这个报错.

select * into b from a where 11 select * from (select a.*,rownum aa from table a ) where aa=10 select *from A where A.a like '%1%'||'%' select * from tb1 a where =(select min(id2) from tb1 where id1=a.id1)其中的a该如何理解? SQL 语句 SELECT * FROM {{table}} WHERE `fleet_end_time` select ** from A where A.id in (select id from B where ****) 在以下哪种情况,select ** from A whereselect ** from A where A.id in (select id from B where ****) 在以下哪种情况,此语句执行的速度快:(1)A表的记录数远多于 oracle查询语句 select a||','||b||','||c from table where a in('m','n') select * from table_a a,table_b b where a.col1 = b.col1(+) ;最后的(+)怎么解释? SQL语句理解 select * from B where (select count(1) as num from A where A.ID = B.ID) = 0select * from B where (select count(1) as num from A where A.ID = B.ID) = 0请问如何理解,为什么 可以在B表中 排除A表的数据 oracle exists函数用法select A.DEPTNO,A.NAME FROM A WHERE EXISTS (SELECT 1 FROM B WHERE A.DEPTNO=B.DEPTNO)中的SELECT 不会是查找是1的值吧? 求教一个mysql语句 select a.column1,tmp.column1 from a ,(select * from b where ...) where ...求教一个mysql语句select a.column1,tmp.column1 from a ,(select * from b where ...) as tmp where ...tmp相当于从另一个表查询出的结果建 sql语句 后面的(+) select * from t1,t2 where t1.a=t2.b(+) HQL 的语法:select a from a where a=3 or select b from b whereb=2 要怎么写? 一个SQL语言,关于ANY 和ALL Q1:SELECT a FROM R WHERE b>= ANY (SELECT d FROM S WHERE c>10);Q2:SELECT a FROM R WHERE b>= ALL(SELECT d FROM S WHERE c>10);(A) Q1和Q2产生的结果一样; (B) Q1的结果总是包含Q2的结果;(C) Q2的结果总是 select * from a union select * from b 能详细说下么 PLSQL中复制表select * into b from a where 11这句话中where 11在这里怎么理解 ms sql :select * from (select *from b) as xxx where 和 select * from (select *from b) xxx where区select * from (select *from b) as xxx where…… 和 select * from (select *from b) xxx where……的区别别告诉我是一样的.因为我有一 select * from user_info where user_name in (select user_name from user)怎么改写提高效率谢谢了.