作业帮几条有关limit的数学题Find the value of c so that f(x) is continuous everywhere. f(x) = sin(3x)+e^(3cx) -1 when x<>0 = x when x=0;请问应该如何计算这一题? 2. f(a) = 3a/(abs(a)
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几条有关limit的数学题Find the value of c so that f(x) is continuous everywhere. f(x) = sin(3x)+e^(3cx) -1 when x<>0 = x when x=0;请问应该如何计算这一题? 2. f(a) = 3a/(abs(a)
几条有关limit的数学题
Find the value of c so that f(x) is continuous everywhere.
f(x) = sin(3x)+e^(3cx) -1 when x<>0
= x when x=0;
请问应该如何计算这一题?
2. f(a) = 3a/(abs(a)+2a) when a<>0
= 0 when a =0;
limit of x tend to 0是什麼?
几条有关limit的数学题Find the value of c so that f(x) is continuous everywhere. f(x) = sin(3x)+e^(3cx) -1 when x<>0 = x when x=0;请问应该如何计算这一题? 2. f(a) = 3a/(abs(a)
1:用等价无穷小：lim f(x)=sin(3x)+e^(3cx) -1=3x+3cx=x(3+3c)
3+3c=1得c=-2/3
2:f(a) = 3a/(|a|+2a) a≠0
lim f(a)=3a/3a=1
lim f(a)=3a/a=3
lim f(a)≠lim f(a)≠f(0)
limit of x tend to 0 这里没有x,是a趋于0吧?这时极限不存在
1:用等价无穷小：lim f(x)<0±>=sin(3x)+e^(3cx) -1=3x+3cx=x(3+3c)
3+3c=1得c=-2/3
2:f(a) = 3a/(|a|+2a) a≠0
lim f(a)<0+>=3a/3a=1
lim f(a)<0->=3a/a=3
lim f(a)<0+>≠lim f(a)<0->≠f(0)
limit o...
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1:用等价无穷小：lim f(x)<0±>=sin(3x)+e^(3cx) -1=3x+3cx=x(3+3c)
3+3c=1得c=-2/3
2:f(a) = 3a/(|a|+2a) a≠0
lim f(a)<0+>=3a/3a=1
lim f(a)<0->=3a/a=3
lim f(a)<0+>≠lim f(a)<0->≠f(0)
limit of x tend to 0 这里没有x，是a趋于0吧？ 这时极限不存在追问第2题我明白了,可是第一题可不可以再说明一下是怎样到sin(3x)+e^(3cx) -1=3x+3cx这步骤?
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