y=x^3-5x^2+2x-8 求y^2求y撇
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y=x^3-5x^2+2x-8 求y^2求y撇
y=x^3-5x^2+2x-8 求y^2
求y撇
y=x^3-5x^2+2x-8 求y^2求y撇
y=x^3-5x^2+2x-8
所以,y^2=(x^3-5x^2+2x-8)^2
=x^6+25x^4+4x^2+64+2x^3*(-5x^2)+2*x^3*(2x)+2x^3*(-8)+2*(-5x^2)*(2x)+2(-5x^2)*(-8)+2*(2x)*(-8)
=x^6+25x^4+4x^2+64-10x^5+4x^4-16x^3-20x^3+80x^2-32x
=x^6-10x^5+29x^4-36x^3+84x^2-32x+64
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