(xy+1)(x+1)(y+1)+xy

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(xy+1)(x+1)(y+1)+xy
(xy+1)(x+1)(y+1)+xy

(xy+1)(x+1)(y+1)+xy
(xy+1)(x+1)(y+1)+xy
=(xy+1)(xy+1+x+y)+xy
=(xy+1)(xy+x+1)+y(xy+1)+xy
=(xy+1)(xy+x+1)+y(xy+1+x)
=(xy+x+1)(xy+y+1)

前两个因式提取xy+1成为（xy+1)(xy+1+x)，后两个提取y成为y(xy+1+x)于是整个式子化成(xy+1)(xy+1+x)+y(xy+1+x),再提取公因式xy+1+x就可以啦。其实这种题多找几个公因式试试就行啦

分不起来

xy-1+x-y (xy+1)(x+1)(y+1)+xy (xy+1)(x+1)(y+1)+xy (xy+1)(x+1)(y+1)+xy 分解因式(xy+1)(x+y+xy+1)+xy .(x+y-2)(x+y-2xy)+(xy-1)^2 因式分解xy-x-y+1 xy+x+y+1因式分解 1-x-y+xy 因式分解因式分解:xy+x+y+1 xy-1+x-y因式分解 xy-x-y+1因式分解钻机XY-1 ,X,Y, 化简xy-1-x+y 计算3xy[2xy-x(y-2)+x-1] xy(xy+1)+xy+3-2(x+y+1/2)-(x+y-1)^2因式分解因式分解（x+y)(x+y+2xy)+(xy+1)(xy-1) 分解因式(x+y)(x+y+2xy)+(xy+1)(xy-1)