已知sin(α-π/6)=1/3 则cos(π/3+α)的值为

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已知sin(α-π/6)=1/3 则cos(π/3+α)的值为

已知sin(α-π/6)=1/3 则cos(π/3+α)的值为
已知sin(α-π/6)=1/3 则cos(π/3+α)的值为

已知sin(α-π/6)=1/3 则cos(π/3+α)的值为

cos(π/3+α)
=sin[π/2-(π/3+α)]
=sin(π/6-α)
=-sin(α-π/6)
=-1/3