lingo 关于and的用法sets:jishu/1..n/:x,h,y;endsets当i>1且i

lingo 关于and的用法sets:jishu/1..n/:x,h,y;endsets当i>1且i lingo 变量超出最多的限制model:sets:q是初始的角度,m是偏转角;plane/a1..a6/:x,y,q,m;links(plane,plane);endsets目标函数;需求约束;@for(links(i,j)|x(i)#ne# x(j) #and# y(i)#ne# y(j):(x(i)+800*t*@cos(q(i)+m(i))-(x(j)+800*t*@cos(q(j lingo中for的用法,说我下标越界,就是那个a的值有问题,可就是找不出来model:sets:gong/1..8/;shou/1..8/;xunhuan/1,2,3/:a;links(gong,shou):x,m;endsetsmax=x(1,3)+x(2,4);@for(gong(I):@for(shou(J):@bnd(0,x(I,J),m(I,J))));@for(xunhuan(k lingo中sets是什么? 关于lingo程序的,sets:A/1..4/:c,b,n;X/A,A/:D;endsetsmin=1.1*n(1)+1.2*n(2)+1.3*n(3)+1.4*n(4);@for(A(i):@sum(A(j):c(i)*D(i,j)=1750);@for(A(i):@sum(A(j):n(i)*D(i,j)=b(i));@for(A(i):@gin(n(i)));@for(A(j):@for(A(i):@gin(D(i,j))));n(1)>n(2);n(2)>n(3);n 关于 LINGO @FOR 语句请问下面的@for 语句中为什么@for(set1(i):@sum(set1(k):x(k))=1); i j k 总是在换啊?model:sets:set1/1..2/:x;set2/1..2/:y;link(set1,set2):a,b;endsets@for(set1(i):@sum(set1(k):x(k))=1);@for(set2(j):@sum(set2(k):y(k)) 请高手帮我找下这个Lingo程序的错误!下面是Lingo程序model:sets:hotel/1..10/;format/1..3/;link(hotel,format):x,y,c;endsetsmin=@sum(link:x*y*c);@for(format(j):@sum(hotel(i):(y(i)*r(i,j)))=num(j)/2);@for(format(j):@sum(hotel(i):(y(i)*r1( 关于lingo的运输问题model:6发点8收点运输问题;sets:warehouses/wh1..wh6/:capacity;vendors/v1..v8/:demand;links(warehouses,vendors):cost,volume;endsets目标函数;min=@sum(links:cost*volume)需求约束;@for(vendors(J):@sum(warehouses(I): lingo 程序如下我的疑惑是其中 这句是什么意思 @for(ps(j)|j#ne#15:z(j)+y(j+1)=b(j));还有为什么要用 |j#ne#15原函数 如图所示 model:sets: cai/1..7/: s,t,p; ps/1..15/: b,y,z; link(cai,ps): x, c;endsets目标函数; min= LINGO问题.这个LINGO的为什么运行不了.关键是S(i,1)=0,和s(i,7)=0..model:sets:si/1..6/;sj/1..7/;st/1..5/:l;sij(si,sj):c,x,s;stj(st,sj):a;sit(si,st):k;endsetsmin=@sum(sij(i,j):c(i,j)*x(i,j));@for(sj(j):@for(si(i)|i#le#5:s(i+1,j)=s(i,j)+x(i 关于一个简单的lingo程序的bug,求求各位大虾,model:sets:time1/1..7/;time2/1..12/:b;link(time1,time2):x;endsetsdata:b=15,15,15,35,40,40,40,30,31,35,30,20;enddatamin=@sum(link(i,j):x(i,j));x(10,1)+x(9,2)+x(8,3)+x(7,4)+x(6,5)+x(5,6)+x(4,7)> 关于LINGO程序lingo程序如下：sets：a/1..5/:x; endsets data:x=1,2,3,4,5;enddata 若知道a(i):x(i)=5,如何写出程序求出i的值 model is ill lingo,高手帮帮忙!1下面的是我写的 但是怎么改都有错!model:sets: varei/1..7/:t,s; varej/1..4/:size,num,p1,p2,g,b,q; links(varei,varej):x,p,m,d;endsets!目标函数;min=@sum(links:m(i,j)*((p(i,j)-p1(j))*b(j)+g(j))*t(i) lingo求矩阵中所有元素的和for循环嵌套sets:l/1..209/;r/1..209/;links(l,r):a,x;endsetsdata:enddatamin=@sum(l(i):@sum(r(j):a(i,j)*x(i,j)));@for(links:@bin(x));@for(l(i):@sum(r(j):x(i,j) lingo @for 我的LINGO程式码在@FOR的地方卡住了,希望大大可以帮我解答一下,万分感激,以下是程式码的部份SETS:SET_PT /1..2/:PT_i; Node i...J average production time/day;SET_TiJ /1..2/:TiJ; Node i...J average transportatio 这样的lingo程序问题出在哪?sets:time/1..88/:income,A,B,rr;fixed/1..6/:g;link(time,fixed):x,y,r,rrr,t;······@for(time(i):@if(t(i,j) #gt# 0,@sum(fixed(j):y(t(i,j),j)*(1+g(j)*r(t(i,j),j)))=x(i,j);,x(i,j)=0));······data部分就省 以下是用lingo写的程序,但不能运行,格式有错吗?请问错在哪里了?model:sets:number/1..32/:A,x,a,z;endsetsmax= @sum(number(j):(A(j)-1)*x(j)*a(j)) ;@for(number(j):x(j)*(A(j)-1)=0,A(j)>=0,z(j)>=0);data:x=60,15,35,10,12.5,75,7.5,90,100 帮看下lingo的程序,model:sets:num1/1..8/:a,b;num2/1..3/:l;aa(num2,num1):x;endsetsdata:a=5,7,5,4,6,5,5,3;b=25,36,32,15,31,28,22,12;enddatamin=0.66*20*Q^0.51+@sum(aa(i,j):x(i,j)*a(j));m1=@sum(num1(j):x(1,j)*b(j));m2=0.9*m1+@sum(num1(j):x(2,j)*b(j)