求值cos9π/4+tan(-11π/6)-sin9π/4+tan(--11π/3)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 11:10:52
求值cos9π/4+tan(-11π/6)-sin9π/4+tan(--11π/3)

求值cos9π/4+tan(-11π/6)-sin9π/4+tan(--11π/3)
求值cos9π/4+tan(-11π/6)-sin9π/4+tan(--11π/3)

求值cos9π/4+tan(-11π/6)-sin9π/4+tan(--11π/3)
cos9π/4+tan(-11π/6)-sin9π/4+tan(--11π/3)
=cos(2π+π/4)+tan(-2π+π/6)-sin(2π+π/4)+tan(-4π+π/3)
=cosπ/4+tanπ/6-sinπ/4+tanπ/3
=√2/2+√3/3-√2/2+√3
=4√3/3

楼上正解呀!si玩意踩呀!