已知数列{an}满足lim[(2n-1)an]=2,则lim(n+2)an=
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 08:58:14
已知数列{an}满足lim[(2n-1)an]=2,则lim(n+2)an=
已知数列{an}满足lim[(2n-1)an]=2,则lim(n+2)an=
已知数列{an}满足lim[(2n-1)an]=2,则lim(n+2)an=
lim[(2n-1)an]=2
lim[(2n-1)an] /[(n+2)an ]= lim (2n-1) / (n+2) = 2
=> lim(n+2)an = 1
已知数列{an}满足lim[(2n-1)an]=2,则lim(n+2)an=
关于数列极限的已知数列an满足a1=0 a2=1 an=(an-1+an-2)/2 求lim(n->无穷)an
数列极限(已知lim[(2n-1)an]=2,求lim n*an)
已知数列﹛an﹜满足lim[﹙3n-1﹚an]=4,则limnan=
已知数列{An}的前n项和Sn满足Sn=1-2/3An.求lim(A1S1+A2S2+…AnSn).
数列{an}满足lim(an+1-an)=a,证明liman/n=a
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
周期性数列问题i已知数列{an}满足a(n+1)=2an (0
已知数列{An}满足A1=1,An+1=2An+2^n.求证数列An/2是等差数列
若数列{an}满足a1=√(6),an+1=√(an+6),(n∈N),如果lim(an)存在,求lim(an)n都趋向无穷大
已知数列{an}、{bn}满足:lim(an-3bn)=1已知数列{an}、{bn}满足:lim(an-3bn)=1,lim(2an+bn)=21)数列{an}、{bn}是否存在极限2)求极限lim(4an-5bn)
已知数列an满足an=1+2+...+n,且1/a1+1/a2+...+1/an
已知数列{an}满足a1=1,an+1·an=2^n 则s2012
已知数列{an}满足a1=1/2,sn=n^2an,求通项an
已知数列{an},满足a1=1/2,Sn=n²×an,求an
已知数列an满足a1=1/2 sn=n平方×an 求an
已知数列An满足 A1=1/2 Sn=N²An 求An
已知数列an满足a1=1 Sn=2an+n 求an